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Speaker Impedance

Combine speakers in series, parallel or series-parallel and I compute the total impedance, the power each one receives and whether the load is safe for your amplifier (minimum stable).

How are they wired?

Parallel: impedance goes down (Z/n). Series: goes up (n·Z).

Ω

Nominal impedance of each speaker. Typical values: 4, 6, 8 or 16 Ω. All equal.

units

Total number of equal speakers connected to this amplifier output.

W

Power the amp delivers into the resulting total impedance. With equal speakers, each gets an equal share.

Ω

Lowest load your amplifier tolerates. Home units: 4 Ω. Robust / class-D amps: 2 Ω. Below this the amp may overheat or fail.

Examples
redzilla.cl — impedance
 
Total impedance
Power per speaker
Headroom over minimum
Z total
W / speaker
Config

Impedance by count

SpeakersZ totalvs minimum

your current configuration · in parallel the impedance drops as you add speakers.

How it is computed · series, parallel and safety

1. Series: impedances add up. Z = Z₁ + Z₂ + … + Zₙ. With n equal speakers of ZZ·n. Example: 2×8 Ω = 16 Ω.

2. Parallel: reciprocals add up. 1/Z = 1/Z₁ + … + 1/Zₙ. With n equal → Z/n. Example: 4×8 Ω = 2 Ω.

3. Series-parallel: you build G groups in parallel, each with N speakers in series. Zgroup = N·Z and Ztotal = Zgroup / G. Example: 4×8 Ω in 2 groups of 2 in series = (2·8)/2 = 8 Ω.

4. Power: the amp delivers P into the total impedance. The voltage across the load is V = √(P·Z). With equal speakers the power splits evenly: each one gets P / n.

5. Safety: if the total impedance falls below the amplifier's minimum stable load, current rises and the amp can overheat, go into protection or fail. Always keep the load the manufacturer's minimum.

Resistive model (nominal impedance, equal speakers). Real impedance varies with frequency; use the nominal value as a design reference.

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How it works

The calculator combines identical speakers in three topologies and returns the total impedance: in series impedances add up (n × Z), in parallel the inverses add and with equal speakers it becomes Z / n, and in series-parallel groups of N speakers in series are connected in parallel: Ztotal = (N × Z) / G. It also splits the amplifier power among the speakers (with equal units each receives P / n) and computes the voltage and current across the load.

The key output is the safety verdict: it compares the total impedance against the amplifier minimum stable load (4 Ω on typical home gear, 2 Ω on robust or class-D amplifiers). If the load falls below it, the amplifier draws more current than it tolerates and can overheat, go into protection or fail; the tool flags it in red and suggests switching to series or series-parallel. The model is resistive using nominal impedance: real impedance varies with frequency, but the nominal value is the correct design reference.

Example: 4 speakers of 8 Ω on an amplifier with a 4 Ω minimum

  1. In parallel: 8 / 4 = 2 Ω, below the 4 Ω minimum: dangerous load.
  2. In series-parallel (2 groups of 2 in series): Zgroup = 2 × 8 = 16 Ω and Ztotal = 16 / 2 = 8 Ω: safe load.
  3. With a 200 W amplifier, each speaker receives 200 / 4 = 50 W in both configurations.

Frequently asked questions

Can I connect two 8-ohm speakers to an amplifier with a 4-ohm minimum?
Yes, in parallel: 2 × 8 Ω in parallel give exactly 4 Ω, right at the minimum stable load. It works, but with no headroom: at high volume keep an eye on the amplifier temperature. In series they would give 16 Ω, completely safe although most amplifiers deliver less power into it.
What happens if the impedance falls below the amplifier minimum?
The output current rises beyond what the stage tolerates: the amplifier overheats, distorts, goes into protection or in the worst case burns out. For example, 3 speakers of 4 Ω in parallel give 1.33 Ω, a dangerous load for almost any equipment. The fix is regrouping in series or series-parallel, or spreading across more channels.
What is the difference between wiring speakers in series and in parallel?
In series impedances add up (2 × 8 Ω = 16 Ω): the load rises, the amplifier runs relaxed but delivers less power. In parallel impedance drops (2 × 8 Ω = 4 Ω): the amplifier delivers more power but draws more current. Series-parallel combines both to keep the original impedance with 4 or more speakers.
Why does the calculator require identical speakers?
Because with different impedances the power splits unevenly: in parallel the lower-impedance speaker receives more power, and in series the higher-impedance one does. That unbalances volume and can overload one unit. With identical speakers the split is exact: each receives P divided by n.
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Disclaimer We take great care to keep every tool accurate and review it thoroughly; even so, we can't guarantee it is free of errors or take responsibility for how the results are used. We recommend double-checking anything critical.
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