Projector Throw Distance
Calculate a projector's mounting distance from the image size, or the image size from the distance, using the throw ratio (fixed or with a zoom range) and the aspect ratio. All in your browser.
How it is calculated · throw ratio and aspect
1. The throw ratio is the
distance divided by the image width (not the
diagonal): throw = distance / width.
2. Width and height come from the diagonal
and the aspect: width = diagonal · aspW / √(aspW² + aspH²)
and height = diagonal · aspH / √(aspW² + aspH²). At 16:9
the width ≈ 0.8716 · diagonal and the height ≈
0.4903 · diagonal.
3. Distance from size:
distance = throw · width. Size from distance:
width = distance / throw, then
diagonal = width / (aspW / √(aspW² + aspH²)).
4. With a throw range (zoom) there is a
minimum and
maximum distance (or size). Conversion:
1 in = 0.0254 m.
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How it works
The calculator solves the typical projector-installation problem: at what distance to mount it to get a given image size (mode A), or what image size you get from a fixed distance (mode B). It works with the projector throw ratio, fixed or with a zoom range (for example 1.2–1.5:1), and with the aspect ratio: 16:9, 16:10, 4:3 or 2.35:1, converting between inches, meters and feet (1 inch = 0.0254 m).
The key detail is that the throw ratio is defined against the image width, not the diagonal: throw = distance ÷ width. Width comes from the diagonal and the aspect via width = diagonal × aspW ÷ √(aspW² + aspH²); in 16:9 the width is ≈ 0.8716 × diagonal and the height ≈ 0.4903 × diagonal. With a zoom lens, the throw range yields a minimum and maximum distance (or size).
Example: 100-inch 16:9 screen with a 1.2–1.5:1 throw
- The width of a 100″ diagonal in 16:9 is
100 × 0.8716 = 87.16″ = 2.21 m(height ≈ 1.25 m). - Minimum distance (zoom at 1.2):
1.2 × 2.21 = 2.66 m. - Maximum distance (zoom at 1.5):
1.5 × 2.21 = 3.32 m: the projector can be mounted anywhere between 2.66 and 3.32 m from the screen.